3.5.14 \(\int \frac {(a+b x^2)^p}{x^2 (d+e x)} \, dx\) [414]

3.5.14.1 Optimal result

Integrand size = 20, antiderivative size = 178 \[ \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx=-\frac {\left (a+b x^2\right )^p \left (1+\frac {b x^2}{a}\right )^{-p} \operatorname {AppellF1}\left (-\frac {1}{2},-p,1,\frac {1}{2},-\frac {b x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d x}-\frac {e^3 \left (a+b x^2\right )^{1+p} \operatorname {Hypergeometric2F1}\left (1,1+p,2+p,\frac {e^2 \left (a+b x^2\right )}{b d^2+a e^2}\right )}{2 d^2 \left (b d^2+a e^2\right ) (1+p)}+\frac {e \left (a+b x^2\right )^{1+p} \operatorname {Hypergeometric2F1}\left (1,1+p,2+p,1+\frac {b x^2}{a}\right )}{2 a d^2 (1+p)} \]

output

-(b*x^2+a)^p*AppellF1(-1/2,1,-p,1/2,e^2*x^2/d^2,-b*x^2/a)/d/x/((1+b*x^2/a) 
^p)-1/2*e^3*(b*x^2+a)^(p+1)*hypergeom([1, p+1],[2+p],e^2*(b*x^2+a)/(a*e^2+ 
b*d^2))/d^2/(a*e^2+b*d^2)/(p+1)+1/2*e*(b*x^2+a)^(p+1)*hypergeom([1, p+1],[ 
2+p],1+b*x^2/a)/a/d^2/(p+1)
 

3.5.14.2 Mathematica [A] (verified)

Time = 0.40 (sec) , antiderivative size = 214, normalized size of antiderivative = 1.20 \[ \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx=\frac {\left (a+b x^2\right )^p \left (\frac {e \left (\frac {e \left (-\sqrt {-\frac {a}{b}}+x\right )}{d+e x}\right )^{-p} \left (\frac {e \left (\sqrt {-\frac {a}{b}}+x\right )}{d+e x}\right )^{-p} \operatorname {AppellF1}\left (-2 p,-p,-p,1-2 p,\frac {d-\sqrt {-\frac {a}{b}} e}{d+e x},\frac {d+\sqrt {-\frac {a}{b}} e}{d+e x}\right )}{p}-\frac {2 d \left (1+\frac {b x^2}{a}\right )^{-p} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},-p,\frac {1}{2},-\frac {b x^2}{a}\right )}{x}-\frac {e \left (1+\frac {a}{b x^2}\right )^{-p} \operatorname {Hypergeometric2F1}\left (-p,-p,1-p,-\frac {a}{b x^2}\right )}{p}\right )}{2 d^2} \]

input

Integrate[(a + b*x^2)^p/(x^2*(d + e*x)),x]
 

output

((a + b*x^2)^p*((e*AppellF1[-2*p, -p, -p, 1 - 2*p, (d - Sqrt[-(a/b)]*e)/(d 
 + e*x), (d + Sqrt[-(a/b)]*e)/(d + e*x)])/(p*((e*(-Sqrt[-(a/b)] + x))/(d + 
 e*x))^p*((e*(Sqrt[-(a/b)] + x))/(d + e*x))^p) - (2*d*Hypergeometric2F1[-1 
/2, -p, 1/2, -((b*x^2)/a)])/(x*(1 + (b*x^2)/a)^p) - (e*Hypergeometric2F1[- 
p, -p, 1 - p, -(a/(b*x^2))])/(p*(1 + a/(b*x^2))^p)))/(2*d^2)
 

3.5.14.3 Rubi [A] (verified)

Time = 0.32 (sec) , antiderivative size = 178, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.350, Rules used = {621, 354, 97, 75, 78, 395, 394}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx\)

\(\Big \downarrow \) 621

\(\displaystyle d \int \frac {\left (b x^2+a\right )^p}{x^2 \left (d^2-e^2 x^2\right )}dx-e \int \frac {\left (b x^2+a\right )^p}{x \left (d^2-e^2 x^2\right )}dx\)

\(\Big \downarrow \) 354

\(\displaystyle d \int \frac {\left (b x^2+a\right )^p}{x^2 \left (d^2-e^2 x^2\right )}dx-\frac {1}{2} e \int \frac {\left (b x^2+a\right )^p}{x^2 \left (d^2-e^2 x^2\right )}dx^2\)

\(\Big \downarrow \) 97

\(\displaystyle d \int \frac {\left (b x^2+a\right )^p}{x^2 \left (d^2-e^2 x^2\right )}dx-\frac {1}{2} e \left (\frac {e^2 \int \frac {\left (b x^2+a\right )^p}{d^2-e^2 x^2}dx^2}{d^2}+\frac {\int \frac {\left (b x^2+a\right )^p}{x^2}dx^2}{d^2}\right )\)

\(\Big \downarrow \) 75

\(\displaystyle d \int \frac {\left (b x^2+a\right )^p}{x^2 \left (d^2-e^2 x^2\right )}dx-\frac {1}{2} e \left (\frac {e^2 \int \frac {\left (b x^2+a\right )^p}{d^2-e^2 x^2}dx^2}{d^2}-\frac {\left (a+b x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {b x^2}{a}+1\right )}{a d^2 (p+1)}\right )\)

\(\Big \downarrow \) 78

\(\displaystyle d \int \frac {\left (b x^2+a\right )^p}{x^2 \left (d^2-e^2 x^2\right )}dx-\frac {1}{2} e \left (\frac {e^2 \left (a+b x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {e^2 \left (b x^2+a\right )}{b d^2+a e^2}\right )}{d^2 (p+1) \left (a e^2+b d^2\right )}-\frac {\left (a+b x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {b x^2}{a}+1\right )}{a d^2 (p+1)}\right )\)

\(\Big \downarrow \) 395

\(\displaystyle d \left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} \int \frac {\left (\frac {b x^2}{a}+1\right )^p}{x^2 \left (d^2-e^2 x^2\right )}dx-\frac {1}{2} e \left (\frac {e^2 \left (a+b x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {e^2 \left (b x^2+a\right )}{b d^2+a e^2}\right )}{d^2 (p+1) \left (a e^2+b d^2\right )}-\frac {\left (a+b x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {b x^2}{a}+1\right )}{a d^2 (p+1)}\right )\)

\(\Big \downarrow \) 394

\(\displaystyle -\frac {\left (a+b x^2\right )^p \left (\frac {b x^2}{a}+1\right )^{-p} \operatorname {AppellF1}\left (-\frac {1}{2},-p,1,\frac {1}{2},-\frac {b x^2}{a},\frac {e^2 x^2}{d^2}\right )}{d x}-\frac {1}{2} e \left (\frac {e^2 \left (a+b x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {e^2 \left (b x^2+a\right )}{b d^2+a e^2}\right )}{d^2 (p+1) \left (a e^2+b d^2\right )}-\frac {\left (a+b x^2\right )^{p+1} \operatorname {Hypergeometric2F1}\left (1,p+1,p+2,\frac {b x^2}{a}+1\right )}{a d^2 (p+1)}\right )\)

input

Int[(a + b*x^2)^p/(x^2*(d + e*x)),x]
 

output

-(((a + b*x^2)^p*AppellF1[-1/2, -p, 1, 1/2, -((b*x^2)/a), (e^2*x^2)/d^2])/ 
(d*x*(1 + (b*x^2)/a)^p)) - (e*((e^2*(a + b*x^2)^(1 + p)*Hypergeometric2F1[ 
1, 1 + p, 2 + p, (e^2*(a + b*x^2))/(b*d^2 + a*e^2)])/(d^2*(b*d^2 + a*e^2)* 
(1 + p)) - ((a + b*x^2)^(1 + p)*Hypergeometric2F1[1, 1 + p, 2 + p, 1 + (b* 
x^2)/a])/(a*d^2*(1 + p))))/2
 

3.5.14.3.1 Defintions of rubi rules used

rule 75

Int[((b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((c + d*x 
)^(n + 1)/(d*(n + 1)*(-d/(b*c))^m))*Hypergeometric2F1[-m, n + 1, n + 2, 1 + 
 d*(x/c)], x] /; FreeQ[{b, c, d, m, n}, x] &&  !IntegerQ[n] && (IntegerQ[m] 
 || GtQ[-d/(b*c), 0])
 

rule 78

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(b 
*c - a*d)^n*((a + b*x)^(m + 1)/(b^(n + 1)*(m + 1)))*Hypergeometric2F1[-n, m 
 + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m}, x] 
 &&  !IntegerQ[m] && IntegerQ[n]
 

rule 97

Int[((e_.) + (f_.)*(x_))^(p_)/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), 
x_] :> Simp[b/(b*c - a*d)   Int[(e + f*x)^p/(a + b*x), x], x] - Simp[d/(b*c 
 - a*d)   Int[(e + f*x)^p/(c + d*x), x], x] /; FreeQ[{a, b, c, d, e, f, p}, 
 x] &&  !IntegerQ[p]
 

rule 354

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.)*((c_) + (d_.)*(x_)^2)^(q_.), x_S 
ymbol] :> Simp[1/2   Subst[Int[x^((m - 1)/2)*(a + b*x)^p*(c + d*x)^q, x], x 
, x^2], x] /; FreeQ[{a, b, c, d, p, q}, x] && NeQ[b*c - a*d, 0] && IntegerQ 
[(m - 1)/2]
 

rule 394

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(q_ 
), x_Symbol] :> Simp[a^p*c^q*((e*x)^(m + 1)/(e*(m + 1)))*AppellF1[(m + 1)/2 
, -p, -q, 1 + (m + 1)/2, (-b)*(x^2/a), (-d)*(x^2/c)], x] /; FreeQ[{a, b, c, 
 d, e, m, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, 1] && (Int 
egerQ[p] || GtQ[a, 0]) && (IntegerQ[q] || GtQ[c, 0])
 

rule 395

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2)^(q_ 
), x_Symbol] :> Simp[a^IntPart[p]*((a + b*x^2)^FracPart[p]/(1 + b*(x^2/a))^ 
FracPart[p])   Int[(e*x)^m*(1 + b*(x^2/a))^p*(c + d*x^2)^q, x], x] /; FreeQ 
[{a, b, c, d, e, m, p, q}, x] && NeQ[b*c - a*d, 0] && NeQ[m, -1] && NeQ[m, 
1] &&  !(IntegerQ[p] || GtQ[a, 0])
 

rule 621

Int[((x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_))/((c_) + (d_.)*(x_)), x_Symbol] 
:> Simp[c   Int[x^m*((a + b*x^2)^p/(c^2 - d^2*x^2)), x], x] - Simp[d   Int[ 
x^(m + 1)*((a + b*x^2)^p/(c^2 - d^2*x^2)), x], x] /; FreeQ[{a, b, c, d, m, 
p}, x]
 

3.5.14.4 Maple [F]

\[\int \frac {\left (b \,x^{2}+a \right )^{p}}{x^{2} \left (e x +d \right )}d x\]

input

int((b*x^2+a)^p/x^2/(e*x+d),x)
 

output

int((b*x^2+a)^p/x^2/(e*x+d),x)
 

3.5.14.5 Fricas [F]

\[ \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{p}}{{\left (e x + d\right )} x^{2}} \,d x } \]

input

integrate((b*x^2+a)^p/x^2/(e*x+d),x, algorithm="fricas")
 

output

integral((b*x^2 + a)^p/(e*x^3 + d*x^2), x)
 

3.5.14.6 Sympy [F(-1)]

Timed out. \[ \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx=\text {Timed out} \]

input

integrate((b*x**2+a)**p/x**2/(e*x+d),x)
 

output

Timed out
 

3.5.14.7 Maxima [F]

\[ \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{p}}{{\left (e x + d\right )} x^{2}} \,d x } \]

input

integrate((b*x^2+a)^p/x^2/(e*x+d),x, algorithm="maxima")
 

output

integrate((b*x^2 + a)^p/((e*x + d)*x^2), x)
 

3.5.14.8 Giac [F]

\[ \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx=\int { \frac {{\left (b x^{2} + a\right )}^{p}}{{\left (e x + d\right )} x^{2}} \,d x } \]

input

integrate((b*x^2+a)^p/x^2/(e*x+d),x, algorithm="giac")
 

output

integrate((b*x^2 + a)^p/((e*x + d)*x^2), x)
 

3.5.14.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\left (a+b x^2\right )^p}{x^2 (d+e x)} \, dx=\int \frac {{\left (b\,x^2+a\right )}^p}{x^2\,\left (d+e\,x\right )} \,d x \]

input

int((a + b*x^2)^p/(x^2*(d + e*x)),x)
 

output

int((a + b*x^2)^p/(x^2*(d + e*x)), x)